7. *Array.map(): the Fibonacci sequence

//https://www.codewars.com/kata/580777ee2e14accd9f000165/train/javascript


function skiponacci(n) {
  if (n === 1) return '1';
  let a = 1, b = 1, arr = [1, 1];
  for (let i = 3; i <= n; i++){
    let c = a + b;
    arr.push(c);
    a = b;
    b = c;
  }
return (arr.map ((el, i) => i % 2 === 0? el : "skip")+'').replace(/,/g, ' ');
}


****************************************** Other solutions from CW:

function skiponacci(n) {
  let arr = [1, 1];
  for (let i = 2; i < n; i++) {
    arr.push(arr[i - 2] + arr[i - 1]);
  }
 return n === 1 ? '1' : arr.map((el,i) => i % 2 !== 0 ? 'skip' : el).join(' ');
}