TS2349: This expression (Result<?, ?>.else) is not callable

[Jack-Works]

Code:

declare function work(): Result<boolean, void>
work().else(true)
// And I think it should accept a function as well `.else(() => heavyWork())`

Error:

(property) else: (<T2>(val: T2) => boolean) | (<T2>(val: T2) => T2)

This expression is not callable.

Each member of the union type
        '(<T2>(val: T2) => boolean) | (<T2>(val: T2) => T2)' has signatures,
but none of those signatures are compatible with each other.(2349)

Playground link

[vultix]

I'd be more than willing to accept a PR for this change.

[GabrielCTroia]

I'm not sure how the else functionality was initially designed but it doesn't seem to work at all, at least in TS 3.8+. I know this is more of a typescript issue 33591 or 7294, but imho it should either be removed or a workaround found.

This being said I'd be more than willing to give it a try once I get some time.

[Jack-Works]

I found a fix for this. Please wait