refactor: Provide a better name for the files variable

The files variable stores the names of files in the current module's
directory that have been recognized as possible license files

lib/index.js

@@ -45,7 +45,7 @@ const flatten = function flatten(options) {
     const moduleInfo = { licenses: UNKNOWN };
     const { color: colorize, deps: json, unknown } = options;
     const currentPackageNameAndVersion = `${json.name}@${json.version}`;
-    let files = [];
+    let licenseFilesInCurrentModuleDirectory = [];
     let licenseData;
     let licenseFile;
     let noticeFiles = [];
@@ -171,10 +171,10 @@ const flatten = function flatten(options) {
 
     /*istanbul ignore else*/
     if (clarification?.licenseFile) {
-        files = [clarification.licenseFile];
+        licenseFilesInCurrentModuleDirectory = [clarification.licenseFile];
     } else if (fs.existsSync(module_path)) {
-        files = licenseFiles(dirFiles);
         const filesInModuleDirectory = fs.readdirSync(module_path);
+        licenseFilesInCurrentModuleDirectory = licenseFiles(filesInModuleDirectory);
 
         noticeFiles = filesInModuleDirectory.filter((filename) => {
             filename = filename.toUpperCase();
@@ -184,7 +184,7 @@ const flatten = function flatten(options) {
         });
     }
 
-    files.forEach(function (filename, index) {
+    licenseFilesInCurrentModuleDirectory.forEach(function (filename, index) {
         licenseFile = path.join(module_path, filename);
         // Checking that the file is in fact a normal file and not a directory for example.
         /*istanbul ignore else*/