How to cleanup object after being borrow_mut ??

[ajaythxkur]

i want to delete object on a specific if condition:
The code goes like this

1. let object = borrow_mut object and change some state in it.
2. An if condition is specified in function, if the condition is achieved i want to delete the object with delete ref.

I can't delete the object with object.delete_ref

[MoonShiesty]

you need to remove all the resources inside of the object before you can destroy it, ie:

move_from<MyType>(object_addr);

then you can cleanup the object with the delete ref. if the delete ref is stored in the resource you can do this:

let MyType {
     delete_ref,
     ..., // other fields
} = move_from<MyType>(object_addr);
object::delete(delete_ref);

[magnum6actual]

That would depend on the abilities of the resources, though, right? All would need 'drop' ability if not handled explicitly.

[kshitjee]

@magnum6actual you need to define the fields to be empty, which effectively "removes" the resources from global storage. Here's what object::delete does:

let object_core = move_from<ObjectCore>(ref.self);
let ObjectCore {
   guid_creation_num: _,
   owner: _,
   allow_ungated_transfer: _,
   transfer_events,
} = object_core;

[ajaythxkur]

let me explain with code what i am trying to achieve
fun(object: Object) acquires SomeStruct {
let some_struct = borrow_global_mut(obj_addr);
some_struct.counter = some_struct.counter + 1;
if(some_struct.counter == 5){
delete object here (can't move from as its mut borrow above)
}
}

[MoonShiesty]

you should be able to borrow within a local scope:

ie:

let isFive = false;
{
    / / borrowed within bracket's local scope
    let some_struct = borrow_global_mut(obj_addr);
    some_struct.counter = some_struct.counter + 1;
    isFive = some_struct.counter == 5;
}
if(isFive){
delete object here (previous borrow is out-of-scope)