fix(query): fix has function in filter #9043
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Currently when we have a language tagged predicate (example: name).
Querying name should return only untagged values. name@. should return
any language.
Consider dataset
<1> <name> "first user" .
<2> <name@en> "second user" .
query (func: uid(1,2)) { uid name} would return "{uid: 1, name: first
user}".
query (func: uid(1,2)) { uid name@.} would return "{{uid: 1, name@.:
"first user"}, {uid: 2, name@.: "second user"}}".
However due to a bug, we are not enforcing this in @filter(has(name)).
So this results in
query (func: has(dgraph.type)) @filter(has(name)) { uid name} results in
"{{uid: 1, name: "first user'}, {uid: 2}}"
Fix: We update @filter(has(name)) to filter on basis of language.
Fixes:
https://linear.app/hypermode/issue/HYP-311/inconsistent-counts-using-has-at-root
---------
Co-authored-by: Harshil Goel <harshil@dgraph.io>
dgraph-bot
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mangalaman93
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harshil-goel
approved these changes
Mar 13, 2024
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Currently when we have a language tagged predicate (example: name). Querying name should return only untagged values. name@. should return any language.
Consider dataset
<1> "first user" .
<2> name@en "second user" .
query (func: uid(1,2)) { uid name} would return "{uid: 1, name: first user}".
query (func: uid(1,2)) { uid name@.} would return "{{uid: 1, name@.: "first user"}, {uid: 2, name@.: "second user"}}".
However due to a bug, we are not enforcing this in @filter(has(name)). So this results in
query (func: has(dgraph.type)) @filter(has(name)) { uid name} results in
"{{uid: 1, name: "first user'}, {uid: 2}}"
Fix: We update @filter(has(name)) to filter on basis of language.